In Javascript from the following string
filterExpress = %1 and %2 and %3 and % and %5 and %6 I need to remove anything following "% " (i.e % and a space) and before the immediately next occurrence of %.
So the output string should be-
%1 and %2 and %3 and %5 and %6 I've tried to use regexp as follows
filterExpress = filterExpress.replace(/ % .*[^%]/, ''); However, this doesn't match the results that I want.
Please help me giving a solution.
Here is a short solution:
var str = '%1 and %2 and %3 and % and %5 and %6';
str.replace(/% .*?%/g, '%'); // "%1 and %2 and %3 and %5 and %6"
Regexp explained:
matches anything starting with %[space] until the first %. It has the global modifier so it doesn't stop after the first match. It matched both %, so one of them is in the replacement string.
Regex that doesn't match the last %
var str='%1 and %2 and %3 and % and %5 and %6';
str=str.replace(/% .+?(?=%)/g,'');
//Match a % followed by a space than then any character until the next %
//but not including it. Also, do a global replace.
Try this:
var str = '%1 and %2 and %3 and % and %6';
var newStr = '';
for(var i = 0; i < str.length; i++){
var c = str[i];
if(c === '%' && str[i+1] === ' '){
i += ' and '.length;
continue;
}
newStr += c;
}
Try any the following-
var str = '%1 and %2 and %3 and % and %5 and %6';
str=str.replace(/% [^%]+%/g, '%'); // "%1 and %2 and %3 and %5 and %6"
alert(str);
var filterExpress = "%1 and %2 and %3 and % and %5 and %6";
//start of logic
while(filterExpress.indexOf("% ")!=-1)
{
filterExpress=filterExpress.substr(0, filterExpress.indexOf("% "))+filterExpress.substr(filterExpress.indexOf("%",filterExpress.indexOf("% ")+1));
}
//end of logic
alert(filterExpress);
