Correct method to write conditional code in clojure

Question

So I am trying to write the below in clojure (Assume all methods below return boolean)

def some_method(a, b)
  if (call_this_method() )
    then_call_this_method()
  else
    new_method()
end

What I got was this:

(defn some-method [a b]
  (if (call_this_method) 
   :then (then-call-this-method) 
   :else (new-method)))

I am pretty new to clojure so am not sure if this feels like the correct manner to solve this. Is there a different approach?

There are examples at clojuredocs.org, start from clojuredocs.org/clojure_core/clojure.core/if — edbond
– edbond, Commented Dec 12, 2013 at 19:53

samsquanch · Accepted Answer · 2013-12-12 19:20:59Z

5

if basically takes 3 params, [condition what-to-run-if-true optional-run-if-false]

(defn some-method
    "My function does ..."
    [ a b ] 
    (if (call-this-method)
        (then-call-this-method)
        (new-method)))

answered Dec 12, 2013 at 19:20

samsquanch

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1 Comment

If you need several clauses in either then or else branch use (do (function1) (function2))

daniel gratzer · Accepted Answer · 2013-12-12 19:22:43Z

5

You can use if in clojure as well

(if test then-code else-code)

Or cond which is more like switch

(cond
    test-A run-if-A
    test-B run-if-B
    ...
    :else else-code)

And if you wanted to do something like

 if(foo) bar;

Then you would write

 (when foo bar)

answered Dec 12, 2013 at 19:22

daniel gratzer

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