I have to select all the files in a directory at a time which has y2001, y2002, and y2003 in the mid of filename. How can I?
import glob
files = glob.glob('*y2001*.jpg')
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docs.python.org/2/library/fnmatch.htmlAshwini Chaudhary– Ashwini Chaudhary2014-01-06 10:59:55 +00:00Commented Jan 6, 2014 at 10:59
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2 Answers
You can do it with
import glob
files = glob.glob('*y200[123]*.jpg')
for futher reference see http://docs.python.org/2/library/glob.html
5 Comments
2964502
thanks btw how to feed them separately y2001, y2002, y2003 . looking for alternative..
Ashwini Chaudhary
@viena There's no need to feed them separately.
2964502
@ Ashwini Chaudhary please give me alternative like y2001 and y2002 and y2003
Ashwini Chaudhary
@viena Use a list comprehension on
os.listdir and filter the list items using either substring match or regex.
Petr Joachim
@viena then consider using
fnmatch.fnmatch in a loop (if you are not satisfied with regex): docs.python.org/2/library/fnmatch.html#fnmatch.fnmatchHere is an overkill method for solving your problem.
import os
import re
import functools
def validate_file(validators, file_path):
return any(re.search(validator, file_path) for validator in validators)
def get_matching_files_in_dir(directory, validator, append_dir=True):
for file_path in os.listdir(directory):
if validator(file_path):
yield os.path.join(directory, file_path) if append_dir else file_path
# define your needs:
matching_patterns = ['y2001', 'y2002', 'y2003']
validator = functools.partial(validate_file, matching_patterns)
# usage
list(get_matching_files_in_dir('YOUR DIR', validator))
An Example:
>>> matching_patterns = ['README']
>>> validator = functools.partial(validate_file, matching_patterns)
>>> print list(get_matching_files_in_dir('C:\\python27', validator))
['C:\\python27\\README.txt']
