How to add parameters to flask-restful in python?

Question

How do I create an api call that does something like:

api.add_resource(MyResource, '/myresource/<myurlparameter>')

It is not clear how I can handle it from within:

class MyResource(restful.Resource):
    def get(self):
        print myurlparameter
        return ""

Also, I noticed I can only add_resource to one level:

api.add_resource(MyResource, '/myresource') # this works
api.add_resource(MyResource, '/myresource/test') # this this not work

twil · Accepted Answer · 2014-01-14 22:11:25Z

3

You can find everything you need in the docs.

Parameter in requests

class TodoSimple(Resource):
    def get(self, todo_id):
        return {todo_id: todos[todo_id]}

    def put(self, todo_id):
        todos[todo_id] = request.form['data']
        return {todo_id: todos[todo_id]}

api.add_resource(TodoSimple, '/<string:todo_id>')

Few endpoints

api.add_resource(HelloWorld,
    '/',
    '/hello')

answered Jan 14, 2014 at 22:11

twil

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