I want to create a fault log. The fault log should be able to store the last 10 faults.
A fault has 3 piece of information: 1. Number of fault. 2. Fault name. 3. Date time of fault.
How can i do this using structs?
Or should i do it using arrays and if so how?
The fault log is for storage in memory only.
I assume you want to store it in the memory, then you can use a combination of struct and array.
Something like will following will do:
typedef struct {
int number;
char* name; // You can use an array instead char name[MAX_FAULT_NAME_LENGTH]
int timestamp;
} fault_entry;
fault_entry fault_log[10];
Of course this is hand-waving. If you want to store it to a file, you need to serialize. You need to think about what data-type to use for date/time and name. But it should help you get started.
A log usually implies some kind of more permanent storage, which might mean that it should be written to a file. If so, then a structure is not necessarily required. It could be implemented as a function that accepts the required information and generates the other information (e.g., time/date).
But if it is indeed more of a temporary type of storage, then it could be stored in a simple circular array. Keep an index of the current position in the array and write to that position.
typedef struct {
int faultNumber;
char faultName[50]; // length should probably be a #define
char faultDate[20]; // date in C could be stored in some kind of char array.
// or it could be something representing results of something
// like a time_t result.
} LOG_ENTRY;
LOG_ENTRY LOGS[10];
int iCurPos = 0;
Then add an entry at the current position and increment iCurPos and loop it back to 0 when it hits the end.
You should use an array of the struct type such as
#define NAME_MAXLEN 20
struct fault {
int number;
time_t time;
char name[NAME_MAXLEN];
};
struct fault faults[10];
];
Something along the lines of:
typedef struct fault
{
int number;
char *name;
char *date;
} fault;
fault faults[10];
faults[0].number = 1;
faults[0].name = "Fault Number 1";
faults[0].date = "Today's Date";
/*etc*/
printf("%d\n", faults[0].number);
printf("%s\n", faults[0].name);
printf("%s\n", faults[0].date);
You will need to decide what time type to use of course. Here, i've used a string.
