Say that I have array MatrixA which is 2x3 and is filled to 0. How do I set up my loop so that values would be read into it but if the user only enters 3 values, the remaining 3 in MatrixA are 0?
Edit:
const int Q = 2;
const int S = 3;
int matrixA[Q][S] = {0};
for(int i = 0; i < Q; i++){
for(int j = 0; j < S; j++){
cin >> matA[i][j];
}
}
Initialize array MatrixA with 0s and then accept values from user. Code would be something like below:
int iOuter = 0;
int iInner = 0;
for (iOuter = 0; i <2; iOuter++)
for (iInner = 0; i < 3; iInner++)
{
MatrixA[iOuter][iInner] = 0;
cin >> MatrixA[iOuter][iInner];
}
Id rather you have code for me to work off of for my answer but assuming your question and statement I will say this. Have a loop in which counts the amount of times the user inputs a number. When the user enters three numbers; Initialize a row variable in which takes the value of 2. Then loop it based on the amount of times the user imputed numbers with a for loop or any other method you choose.
Also to answer your question about the remaining 3 numbers I have provided a link below about the array uninitialized indexes
const int Q = 2;
const int S = 3;
int flag = 0;
int matrixA[Q][S] = {0};
for(int i = 0; i < Q; i++){
for(int j = 0; j < S; j++){
matA[i][j] = 0;
}
}
for(int i = 0; i < Q; i++){
for(int j = 0; j < S; j++){
if(getline(cin, matA[i][j])){
}
else{
flag = 1;
break;
}
}
if(flag == 1){
break;
}
}
Let me know if that helps.. :)
