How concatenate strings and display that formated string in linux bash script?

Question

i write below script

#!/bin/bash

str1="apple"
str2="banana"
str3="NA"
str4="lumia"
str5="nokia"

let maxarg=5

checkindex()
{
   while [ $maxarg -gt 0 ]
   do
        str="${str$maxarg}" //here is problem
        echo -e $str
        if [ "${str}" == "NA" ]
        then
            break
        fi

     ((maxarg--))
   done     

   printf "Index is %d\n" $maxarg
}

checkindex

when exicuting it i got str1,str2....Index is 0 output but what i want to print apple,banana....Index is 3 means catch the index where NA string found. Using str="${str$maxarg}"i tried to redirect the output of str1,str2....str5 in str because i am not going to use any switch case or if..else for comparing each string. Any help?

devnull · Accepted Answer · 2014-01-29 10:15:25Z

2

You need to refer to indirect expansion. Replacing the line

    str="${str$maxarg}" //here is problem

with

    tmp="str${maxarg}"   # This sets the variable tmp to str1 and so on
    str=${!tmp}          # This performs indirect expansion to retrieve
                         # the value of the variable name stored in tmp

should make it work.

answered Jan 29, 2014 at 10:15

devnull

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