Spring application context : access web.xml context-params?

Question

Greetings ,

Is there any way to get values from web.xml context-param into Spring context?

For example I define the value in web.xml as :

<context-param>
  <param-name>compass-index</param-name>
  <param-value>file:///home/compass/index</param-value>
</context-param>

And I want to assign that value to the bean-property as:

<bean ...>
<props>
  <prop key="compass.engine.connection">
    ${from web.xml context-param?}
  </prop>
</props>
</bean>

Thanks in advance?

Paul · Accepted Answer · 2011-06-15 19:24:15Z

25

Yes - ServletContextPropertyPlaceholderConfigurer

This article explains the details. In short, you need:

<bean class="org.springframework.web.context.support.ServletContextPropertyPlaceholderConfigurer">
</bean>

and then use the properties like:

<bean ...>
   <property name="compassIndex" value="${compass-index}" />
</bean>

or with @Value("${compass-index}")

edited Jun 15, 2011 at 19:24

Paul

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answered Feb 1, 2010 at 8:46

Bozho

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5 Comments

Petr Gladkikh Over a year ago

As of Spring 3.1 class ServletContextPropertyPlaceholderConfigurer is deprecated (see javadocs for details).

Bozho Over a year ago

Thanks. So look at the deprecation instructions at static.springsource.org/spring/docs/3.1.x/javadoc-api/org/…

Askar Kalykov Over a year ago

Especially "cool" feature in spring docs is the fact that deprecation has been mentioned, but no updated sample code has been provided.

Pytry Over a year ago

@Askar Kalkov The documentation is not very clear on what you have to do, but in the end it's actually quite simple. See this answer: stackoverflow.com/a/21175824/1669464

Anthony Hayward Over a year ago

This seems like the correct XML since ServletContextPropertyPlaceholderConfigurer was deprecated: <bean class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer"> <property name="environment"><bean class="org.springframework.web.context.support.StandardServletEnvironment" /></property> </bean>

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