Is there is no needs of declaring NSInteger using the alloc and initialise keyword? and why?
I was trying doing NSInteger *choice = [[NSInteger alloc] init]; while I found direct assignment
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possible duplicate of When to use NSInteger vs int?Black Frog– Black Frog2014-02-16 09:39:01 +00:00Commented Feb 16, 2014 at 9:39
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2 Answers
NSInteger is just typedef of int or long (depends on platform)
So you can initialize something like that
NSInteger i = 10;
Quote from SDK documentation
NSInteger Used to describe an integer.
typedef long NSInteger;
When building 32-bit applications, NSInteger is a 32-bit integer. A 64-bit application treats NSInteger as a 64-bit integer.
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NSInteger is not an Objective-C object. It's a datatype (much like C's int or char types). You do not need to call "alloc" (to explicitly allocate memory space) for it.
You can read up on the other Objective-C data types (like NSRange, which you'll use a lot of once you get into NSString objects) in this Apple documentation.
answered Feb 16, 2014 at 9:36
Michael Dautermann
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