Splitting a string based on Pattern Java

Question

Hi I have log files of the following pattern-

2014-03-06 03:21:45,432 ERROR [mfs:pool-3-thread-19] dispatcher.StatusNotification  - Error processing notification. Operation aborted.
java.sql.SQLException: Network error IOException: Connection timed out: connect
2014-03-06 03:22:06,454 ERROR [mfs:pool-3-thread-19] dispatcher.ClientStatusNotification  - Error processing notification. Operation aborted.
java.sql.SQLException: Network error IOException: Connection timed out: connect
2014-03-06 03:22:27,462 ERROR [pool-1-thread-1] cluster.ClusterServiceImpl  - unexpected error when trying to update LastCheckinTime
java.sql.SQLException: Network error IOException: Connection timed out: connect
...

I am trying to split the string into substrings such that-

parsedString[0]=2014-03-06 03:21:45
parsedString[1]=,432 ERROR [mfs:pool-3-thread-19] dispatcher.StatusNotification  - Error processing notification. Operation aborted.
java.sql.SQLException: Network error IOException: Connection timed out: connect
parsedString[2]=2014-03-06 03:22:06
....

I tried using string.split(datepattern) but it only gives me the content in the string array and not the dates. I also tried using Pattern matcher but it only gives me a list of matching dates and not the content.

How do I get both values into the same string array. Any help would be much appreciated. Thanks

Edit- String pattern="([0-9]{4}-[0-1][0-9]-[0-3][0-9]\s(?:[0-1][0-9]|[2][0-3]):[0-5][0-9]:[0-5][0-9],)"; String parsedLogMessage[]=GetLogString().split(pattern); this.MessageContent=Arrays.asList(parsedLogMessage);

This only gives the string split by regex and not the regex string itself

So you can't just split on the comma? Or just grab the index of the comma and then substring? — Dan Temple
– Dan Temple, Commented Mar 12, 2014 at 8:40
No commas appear several times in the content so I don't think that'll be possible .I need to split on datetime values only — user3370268
– user3370268, Commented Mar 12, 2014 at 8:52

piet.t · Accepted Answer · 2014-03-12 08:43:36Z

3

If you must use regex you could try it like this

Pattern p = Pattern.compile("(^[^,]*)(.*$)");
Matcher m = p.matcher(inputstring);
m.matches();
String part1 = m.group(1);
String part2 = m.group(2);

Then part1 should be everything up to the first comma, part2 the rest of the inputstring.

Using substring would be easier though...

answered Mar 12, 2014 at 8:43

piet.t

11.9k21 gold badges45 silver badges56 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

prasanth Over a year ago

But this works for only one line. Pattern.compile("(^[^,]*)(.*$)",Pattern.MULTILINE) would do.

piet.t Over a year ago

of course it has to go into a loop over all lines - either starting before p.matcher, then my solution would suffice, or before m.matches which would require the MULTILINE approach

gerrytan · Accepted Answer · 2014-03-12 08:56:47Z

1

This will split the string each time a comma or a \n newline is found:

String[] parsedString = logString.split("(,|\n)");

It should produce your desired output, but there are few potential problem I foresee here:

First I have a feeling you're trying to load the whole log file into a string first. This is a good waste of memory if you will be processing them by line (what happens if the log file is 10GB?). A better approach would be to use a BufferedReader and do them per line.

Secondly keep in mind a log output can have commas in itself, so above code will be buggy. Since the prefix part seem to be fixed-length, you might want to chop them using substring instead.

answered Mar 12, 2014 at 8:56

gerrytan

41.2k12 gold badges88 silver badges99 bronze badges

2 Comments

user3370268 Over a year ago

Thanks for the lack of a more direct answer I am accepting this.And yes you are probably right loading the whole log file into a string is a waste of good memory.

tero17 Over a year ago

i have string which contains this char '|' i wanna split my string due to this special char is it possible with split ?

Deva · Accepted Answer · 2017-06-06 07:13:28Z

Suppose your string parameters in between two special charaters like : #parameter# or parameter or even two differnt signs at a time like *paramter#. We can have list of all these parameters between those signs by this code :

import java.util.ArrayList;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.commons.lang.StringUtils;

public class Splitter {

    public static void main(String[] args) {

        String pattern1 = "#";
        String pattern2 = "#";
        String text = "(#n1_1#/#n2_2#)*2/#n1_1#*34/#n4_4#";

        Pattern p = Pattern.compile(Pattern.quote(pattern1) + "(.*?)" + Pattern.quote(pattern2));
        Matcher m = p.matcher(text);
        while (m.find()) {
            ArrayList parameters = new ArrayList<>();
            parameters.add(m.group(1));
            System.out.println(parameters);
            ArrayList result = new ArrayList<>();
            result.add(parameters);
            // System.out.println(result.size());
        }

    }
}

Here list result will have parameters n1_1,n2_2,n4_4.

Collectives™ on Stack Overflow

Splitting a string based on Pattern Java

3 Answers 3

2 Comments

2 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related