how to count length of arrays created dynamically?

Question

I have an array

dump($data);
*************************************

    array(10) {
      ["12-male"] => string(1) "2"
      ["11-male"] => string(1) "2"
      ["10-female"] => string(1) "2"
      ["16-female"] => string(1) "2"
      ["9-male"] => string(1) "2"
      ["17-male"] => string(1) "4"
      ["14-male"] => string(1) "4"
      ["15-female"] => string(1) "4"
      ["13-female"] => string(1) "5"
      ["18-female"] => string(1) "6"
    }

******************************************

I am DYNAMICALLY getting like sub arrays out of the array above

$rooms = array();
foreach ($data as $key => $value) {
    $rooms['room'.$value][] = $key;
        $rooms['room'.$value]['count'] = sizeof($rooms['room'.$value]);
}

        dump($rooms);

******************************************

I get this result

Dump => array(4) {
  ["room2"] => array(6) {             //array size=6
    [0] => string(7) "12-male"
    ["count"] => int(6)               //count of array size=6
    [1] => string(7) "11-male"
    [2] => string(9) "10-female"
    [3] => string(9) "16-female"
    [4] => string(6) "9-male"
  }
  ["room4"] => array(4) {             //array size=4
    [0] => string(7) "17-male"
    ["count"] => int(4)               //count of array size=4
    [1] => string(7) "14-male"
    [2] => string(9) "15-female"
  }
  ["room5"] => array(2) {             //array size=2
    [0] => string(9) "13-female"
    ["count"] => int(1)               //count of array size=1 (the problem here)
  }
  ["room6"] => array(2) {             //array size=2
    [0] => string(9) "18-female"
    ["count"] => int(1)               //count of array size=1 (the problem here)
  }
}

My issue is that, the count is returned correctly after first 2 iterations, after that the count is always showing 1, no matter the size of array. I tried count() as well but the result is the same.

xdazz · Accepted Answer · 2014-03-14 09:48:10Z

5

You could do like below:

$rooms = array();
foreach ($data as $key => $value) {
    if (!isset($rooms['room'.$value])) {
         $rooms['room'.$value] = array('count' => 0);
    }
    $rooms['room'.$value][] = $key;
    $rooms['room'.$value]['count']++;
}

But you don't need to add the count into your array.

answered Mar 14, 2014 at 9:48

xdazz

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4 Comments

VostanAzatyan Over a year ago

And what if i want to keep the count in the same array?

xdazz Over a year ago

@user3269869 Does the answer give you the result you expected?

VostanAzatyan Over a year ago

yes that helped me a lot, thanks .... but can you tell me how can i insert count in my created array ?

xdazz Over a year ago

@user3269869 The code already did that, not? Although I do not recommend that.

DorianFM · Accepted Answer · 2014-03-14 09:52:18Z

3

The reason the count is doing that is that from room2 and room4 you are inserting 'count' on the first iteration, then on subsequent iterations 'count' is included in the sizeof() request. For room 5 and room6 as they are iterated only once sizeof() is only called once, before 'count' is inserted into the array, so it's not the index of 'count' not included in the result of sizeof for those items.

answered Mar 14, 2014 at 9:52

DorianFM

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