Android dynamically creating a Button

Question

I am quite new to Android, and is having problem in creating a Button dynamically. I have it working by creating in the Xml layout and working fine. Hope someone can help, to write code to create the button below during runtime, and after that Add it into a TableRow.

Note: I wanted to create a Button which is equivalent to the Xml below, but NOT using findViewById(), because this button doesn't exist. I know how to new a Button, but I am having difficulties on setting all the attributes below. Especially the layout_weight, background and drawableTop.

<Button
    android:id="@+id/BtnRating1"
    android:layout_weight="1"
    android:layout_height="wrap_content"
    android:text="@string/Rating_1"
    android:drawableTop="@drawable/face_1"
    style="?android:attr/borderlessButtonStyle"
    android:background="?android:selectableItemBackground"
    android:gravity="center"
    android:onClick="OnRating_1" />

The below solution may be useful for u stackoverflow.com/questions/21333867/… — Biplab
– Biplab, Commented Mar 20, 2014 at 5:52

Pulkit Sethi · Accepted Answer · 2014-03-20 08:17:18Z

1

Assuming the above xml is named button_view.xml

View view = LayoutInflater.from(context).inflate(R.layout.button_view);
Button button = (Button) view.findViewById(R.id.BtnRating1);

This way you can inflate directly from xml

edited Mar 20, 2014 at 8:17

answered Mar 20, 2014 at 5:10

Pulkit Sethi

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halfer · Accepted Answer · 2018-07-31 23:30:40Z

0

I gave you code how to create a button on dynamic time, you can set all property which you want for this button.

Button myButton = new Button(this);
    myButton.setText("Push Me");

LinearLayout ll = (LinearLayout)findViewById(R.id.BtnRating1);
LayoutParams lp = new LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT);
ll.addView(myButton, lp);

edited Jul 31, 2018 at 23:30

halfer

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answered Mar 20, 2014 at 5:07

Bhanu Sharma

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halfer · Accepted Answer · 2018-07-31 23:31:11Z

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This below line will create the button programetically

Button btn = new Button(ActivityContext);

Then you can also add button properties as below

RelativeLayout.LayoutParams btnparamLayoutParams = new RelativeLayout.LayoutParams(
                RelativeLayout.LayoutParams.MATCH_PARENT, 90);
        btn.setGravity(Gravity.CENTER_VERTICAL);
        btnparamLayoutParams.height = adjustedDp;
        btn1paramLayoutParams.setMargins(0, 0, 0, 100);
        btn.setLayoutParams(btnparamLayoutParams);
        btn.setBackgroundColor(Color.WHITE);

at the end add your button to the parentlayout.

LinearLayout ll = (LinearLayout)findViewById(R.id.linID);
ll.addView(btn)

edited Jul 31, 2018 at 23:31

halfer

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answered Mar 20, 2014 at 6:00

Biplab

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halfer · Accepted Answer · 2018-07-31 23:31:51Z

0

You can do it in two way

create a table row layout with button and inflate it.
you can create button dynamically and add it in your table row see below code for creating buttons dynamically.

 TableRow.LayoutParams params = new TableRow.LayoutParams(TableRow.LayoutParams.WRAP_CONTENT,TableRow.LayoutParams.WRAP_CONTENT);
    Button button = new Button(this);
    params.weight = 1;
    params.gravity = Gravity.CENTER;
    tablerow.addView(button,params);

Here this is context of activity.

edited Jul 31, 2018 at 23:31

halfer

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answered Mar 20, 2014 at 6:04

maddy d

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