SFML: no matching function to Thread()

Question

I try to use a SFML Thread in my game, but I got a problem with it. My code:

void MyGame::endGame()
{
    sf::Thread thread(&PuzzleGame::endThread);
    thread.Launch();
}

void MyGame::endThread()
{

}

As a result I get:

../src/MyGame.cpp: In member function ‘void MyGame::endGame()’:
../src/MyGame.cpp:186:51: error: no matching function for call to ‘sf::Thread::Thread(void (MyGame::*)())’
sf::Thread thread(&MyGame::endThread);
                                    ^

What can be a problem?

EDIT I use SFML 1.6

John_Burchell · Accepted Answer · 2014-03-23 21:34:14Z

1

thread.launch();

Note the lowercase.

Here's the docs in case you're interested:

http://www.sfml-dev.org/tutorials/2.0/system-thread.php

answered Mar 23, 2014 at 21:34

John_Burchell

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1 Comment

archibaldis Over a year ago

Forgot to mention: I use SFML 1.6.

nvoigt · Accepted Answer · 2014-03-24 07:26:44Z

If you want to pass a class-function, you need to pass the object that you want to call it on, too:

void MyGame::endGame()
{
    sf::Thread thread(&MyGame::endThread, this);
    thread.launch();
}

void MyGame::endThread()
{

}

Alternatively you can use a static class method:

void MyGame::endGame()
{
    sf::Thread thread(&MyGame::endThread);
    thread.launch();
}

static void MyGame::endThread()
{

}

Please read the full documentation on SFML threads. Creating a local variable of a thread is not helpful. It will be destroyed when going out of scope and you want the thread to run, not to be deleted.

I see you are using the old SFML 1.6. Please read the tutorial carefully. With the old version, you can only use the second option from the two above. You may want to switch to 2.0 or 2.1 as soon as you can.

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