How to sort in python based on two parameters but with different orders

Question

I read https://wiki.python.org/moin/HowTo/Sorting

>>> sorted(student_tuples, key=itemgetter(1, 0)) [('andrew', 14, 15), ('jane', 12, 10), (zach, 14, 12)]

I can sort in two ways but I want to sort in reverse order with the first parameter but not on the second so I get something like

[('andrew', 14, 15), ('zach', 14, 12), ('jane', 12, 10)]

How can I do that with the reverse=True parameter?

Currently if I use >>> sorted(student_tuples, key=itemgetter(1, 0), reverse=True) both of the sorting orders will be from the highest to lowest. I want only one to be from highest to lowest.

Your example is not clear. Can you please explain with a better example? — thefourtheye
– thefourtheye, Commented Mar 29, 2014 at 7:54

James Sapam · Accepted Answer · 2014-03-29 08:36:35Z

1

Is this you are looking for:

>>> sorted(st, key=lambda x: (x[1]*-1,x[0]))
[('andrew', 14, 15), ('zach', 14, 12), ('jane', 12, 10)]
>>>

edited Mar 29, 2014 at 8:36

answered Mar 29, 2014 at 8:17

James Sapam

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1 Comment

biw Over a year ago

I am looking for the combo of them both. SOrting by value of the second item first in descending order, then by the alphabetical order of the first.

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