When the program is run display function gets called. But not able to understand how?
class A
{
class B
{
void display()
{
System.out.println("display in B.....");
}
}
}
class Twenty extends A.B
{
Twenty(A temp)
{
temp.super();
}
public static void main(String args[])
{
A obj=new A();
Twenty abc=new Twenty(obj);
abc.display();
}
}
explain this program
This is as simple as a class Twenty extending a class B.
Since there is a method display in the B class, Twenty inherits this method as if this method is declared in it. This is why you are able to call the display method on an object of the class Twenty which is abc.
Simple inheritance, Twenty calling the ".super()" from its constructor and since Twenty extends A & B then calling the method "display()" will give you this result
As class Twenty extends from class B it can access its non private methods .(Simple )
You extended Twenty class from B class: class Twenty extends A.B. Than you call display() on instance of the Twenty so inherited display method is invoked.
You can access inner class method from an outer class. Here outer class is A and that is the object you are passing to constructor in your main method.Also, it obeys inheritance. Because of these two reasons, "display" method is getting invoked.
temp.super()?