How do i Extract integer value from a string in Unix

Question

when i type this command /usr/local/afs7/bin/afs_paftools -a about.afs | grep TOTAL_DOCUMENTS

I get a result

TOTAL_DOCUMENTS = 74195

How i can extract the integer number(74195) after = using grep command

Fredrik Pihl · Accepted Answer · 2014-04-08 18:25:34Z

2

One way is to use grep:

$ echo "TOTAL_DOCUMENTS = 74195" | grep -o '[0-9]\+'
74195

or since you know, that it's the last field, use awk:

$ echo "TOTAL_DOCUMENTS = 74195" | awk '{print $NF}'
74195

or just use awk for the lot:

your-command -a about.afs | awk '/TOTAL_DOCUMENTS/{print $NF}'

answered Apr 8, 2014 at 18:25

Fredrik Pihl

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Comments

Jotne · Accepted Answer · 2014-04-08 18:34:52Z

0

If there are no space:

TOTAL_DOCUMENTS=74195

Use this awk

echo "TOTAL_DOCUMENTS=74195" | awk -F= '{print $NF}'
74195

answered Apr 8, 2014 at 18:34

Jotne

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