Java Overloading

Question

I have been asked this question in an interview.

can anyone explain it.

public class A{

     public void show(List <String>list1,List<Integer>lists2){...}

     public void show(List <Integer>list1,List<String>lists2){...}
}
public class B{
 public static void main(..){
    A a=new A();
    List<String> list1;
    List<Integer>lists2;
    a.show(list1,lists2);
     }
   }

I said 2 function would be called.. but when i worte in neatbeans it gave error of same name function been called...??? why so isnt overloading concept used here???

Your code won't compile. Both your show methods have the same erasure. — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Apr 16, 2014 at 16:57

Luiggi Mendoza · Accepted Answer · 2014-04-16 16:57:58Z

6

Due to type erasure, the arguments of the method will become List.

public void show(List list1, List list2);
public void show(List list1, List list2);

Thus becoming invalid code.

answered Apr 16, 2014 at 16:57

Luiggi Mendoza

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Comments

Sandy Simonton · Accepted Answer · 2014-04-16 17:06:39Z

1

Java Generics are enforced at compile time, but the type of the Collection is erased, and what you're left with is a duplicate method. In an IDE, you would get some message about "same type erasure."

Here's a good discussion about it that I enjoyed:

http://mindprod.com/jgloss/generics.html

answered Apr 16, 2014 at 17:06

Sandy Simonton

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ccjmne · Accepted Answer · 2014-07-14 07:00:43Z

0

First, remove "public" from one of your class declaration (actually from class A) .

Second, the compiler is reading the parameter as show(list, list), so it is giving you the same method and there is no overloading occurring here. As both parameters are show(list, list).

Remember, generics are used to distinguish the object type not the return type.

Hope it works.

edited Jul 14, 2014 at 7:00

ccjmne

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answered Jul 14, 2014 at 6:39

AKS

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