detect string between brackets using regex

Question

How can i use regex in python to detect in one file only the stings between the brackets? So If i have some text like this:

</seg>
<src>Sono stati riportati casi di (sgomberi forzati) e violazioni dei diritti umani da parte della polizia, ma su scala minore rispetto agli anni precedenti.</src>

and I want to detect only (sgomberi forzati)

I use the

for line  in file.readlines():
    m=re.compile('\((.*?)\)', re.DOTALL).findall(line)
    print m

but it does not print what I need: it prints also brackets empty like this

[]
[u'sgomberi forzati']

"but it does not return what I need". Makes sense. It's not returning anything because you don't have a return statement anywhere in your code. If you mean "It doesn't print what I need": it works for me. Unless you want it to print something other than ['regional economies', 'transportation']? Please describe what kind of output you expect. — Kevin
– Kevin, Commented Apr 28, 2014 at 12:22
what I need is the srings between the brackets, i.e (regional economies), (transportation). — sss
– sss, Commented Apr 28, 2014 at 12:33
Yes, and that is exactly what is being printed. So you don't actually have a problem, then? — Kevin
– Kevin, Commented Apr 28, 2014 at 12:34

sshashank124 · Accepted Answer · 2014-04-28 12:13:54Z

1

Escape your () as follows:

m = re.compile('\((.*?)\)', re.DOTALL).findall(line)

answered Apr 28, 2014 at 12:13

sshashank124

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2 Comments

sshashank124 Over a year ago

@user3573552, Wait a minute, I swear you just had '((.*?))'. You are someone else changed your code. o.O

Kevin Over a year ago

The slashes were present but not visible in the first version of the code. When it was put in code blocks, they appeared.

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