Use Variable in object echo [duplicate]

Question

$data = file_get_contents("API LINK HERE");
$json = json_decode($data);

echo($json->zhohar->name);

What I want to do is replace zhohar in the echo with a variable which is defined by user input. So in the end I have something like this

$username = $_POST['username'];

$data = file_get_contents("API LINK HERE");
$json = json_decode($data);

echo($json->$username->name);

But this obviously doesn't work. Anyone has an idea how to solve this?

Mahdi · Accepted Answer · 2014-05-02 17:47:28Z

1

You can do something like this:

echo $json->{$username}->name

Or:

$json = json_decode( $data, true );
echo $json[$username]['name'];

answered May 2, 2014 at 17:47

Mahdi

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2 Comments

@dm03514 You're right, my bad.

@vplusm Welcome, but actually I shouldn't answer this one as it is duplicated and has been already answered before.