PHP syntax error when declaring a constant

Question

The error I'm getting here is:

Parse error: syntax error, unexpected 'CASE' (T_CASE), expecting identifier (T_STRING) in [filename] on line 4

<?php

class PartCategories {
    const CASE = 1;
    const PROCESSOR = 2;
    const HARD_DRIVE = 3;
    const MEMORY = 4;
}

Can't say I've tried anything but for the life of me can't see what's wrong here.

Why is this a syntax error?

CASE is a reserved word in PHP, used as part of a switch statement — Mark Baker
– Mark Baker, Commented May 29, 2014 at 11:41
yes CASE is a reserved word. Please change to some other name. — prava
– prava, Commented May 29, 2014 at 11:42
I'm aware of that but assumed it's not that because it's uppercase. — rtheunissen
– rtheunissen, Commented May 29, 2014 at 11:42

Kokos · Accepted Answer · 2014-05-29 11:43:08Z

3

case or CASE is already reserved by PHP for the switch statement. You can't redefine this as a constant, just as you cant define a const FUNCTION or something similar.

You're going to have to change the name of the constant.

answered May 29, 2014 at 11:43

Kokos

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2 Comments

asprin Over a year ago

Would have +1'ed this had Mark not commented before you :p

AeJey Over a year ago

@aspirin: you said it. :P

intekhab · Accepted Answer · 2014-05-29 12:15:36Z

0

First of all you should know that PHP is not case sensitive. So "case", "Case", "caSE", "CAsE" and like are same thing.

And you already know that case is a php reserved keyword it can't be use for variable name.

You can initialize your class like $obj = new PartCategories();
or paRTCATEgories();
or PARTCATEGORIES();
mEANS tO sAY THAt PHp iS CaSE INSEnsitive.

answered May 29, 2014 at 12:15

intekhab

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