How to validate url in java?

Question

I have one inputtext Where I have to enter a link .
How I am going to validate that string is a url(link) or not. Example-

Pattern p = Pattern
                .compile("(@)?(href=')?(HREF=')?(HREF=\")?(href=\")?(http://)?[a-zA-Z_0-9\\-]+(\\.\\w[a-zA-Z_0-9\\-]+)+(/[#&\\n\\-=?\\+\\%/\\.\\w]+)?");

        Matcher m = p.matcher("https://mail.google.com");
        System.out.println(m.matches());

This code gives also false.I am not getting what was the problem in that code.
Or please refer another logic to validate the url.
I had already used UrlValidator urlValidator = new UrlValidator();
But I dont want to use this .jar

This is the another method this method validate properly but I that url is not available.How to check this requirement? example-

public static void main(String[] args) {
        String b = "http://11155555.com/";
        System.out.println(isUrl(b));

    }

    public static boolean isUrl(String str) {
        Pattern urlPattern = Pattern.compile(
                "((https?|ftp|gopher|telnet|file):((//)|(\\\\\\\\))+[\\\\w\\\\d:#@%/;$()~_?\\\\+-=\\\\\\\\\\\\.&]*)",
                Pattern.CASE_INSENSITIVE);
        Matcher matcher = urlPattern.matcher(str);
        if (matcher.find()) {
            return true;
        } else {
            return false;
        }
    }

Thanks in advanced.

Java is to Javascript as ham is to hamster. Please pay attention to your tags. — Boris the Spider
– Boris the Spider, Commented Jun 24, 2014 at 10:16
URL has a String constructor that throws a MalformedURLException... — Boris the Spider
– Boris the Spider, Commented Jun 24, 2014 at 10:17

Keval Trivedi · Accepted Answer · 2014-06-24 10:14:28Z

-1

Try this one :

 public static boolean isUrl(String str){
    Pattern urlPattern = Pattern.compile("((https?|ftp|gopher|telnet|file):((//)|(\\\\\\\\))+[\\\\w\\\\d:#@%/;$()~_?\\\\+-=\\\\\\\\\\\\.&]*)",Pattern.CASE_INSENSITIVE);
         Matcher matcher = urlPattern.matcher(str);
    if (matcher.find()) 
             return true;
        else
            return false;
}

answered Jun 24, 2014 at 10:14

Keval Trivedi

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9 Comments

vijayk Over a year ago

This function gives required output but this is correct method to check?

Keval Trivedi Over a year ago

@vijayk Yes what is the problem with that ?

vijayk Over a year ago

I just confirm . I dont have problem.

Keval Trivedi Over a year ago

also find the another solution : stackoverflow.com/questions/15009573/url-validation-in-java

vijayk Over a year ago

Suppose this is the example 11155555.com which is return true but this is not a valid url. Then how can you check it?

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