Executing for loop inside if statement

Question

I can't figure it out why my program won't start executing the for loop: the logic for the for loop is correct, but when the program runs it just skips the for loop, without executing it. If i is equal to count, it should read last remaining elements from array called se and write to array finallyDone.

while(check && i < len){
    int fi = first[i];
    int se = second[j];
    if(fi < se){
        finallyDone[count] = fi;
        i++;
    }
    else{
        finallyDone[count] = se;
        j++;
    }
    int l;
    if(i >= len){
        for(l = count; l < len * 2 - count; l++){
            finallyDone[count + 1] = se;
        }
        check = false;
    }
    count++;
}

Just debug it. check is probably false and/or i is smaller than len — L-Four
– L-Four, Commented Jul 4, 2014 at 7:05
To figure the for loop, we need to know the value of count and len upon the loop. And from this portion of code, I won't know the value of both of them. Therefore just trace through the loop with a debugger. — Sky
– Sky, Commented Jul 4, 2014 at 7:07

Sayse · Accepted Answer · 2014-07-04 07:22:52Z

3

This is where it goes wrong:

while(check && i < len){
   //and later
    if(i >= len){

You can only walk to the IF-statement if i is smaller than len, but you will only walk into the IF-statement if i is equal to len or bigger. Those two statements are contradictory.

edited Jul 4, 2014 at 7:22

Sayse

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answered Jul 4, 2014 at 7:19

Ward

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2 Comments

MarkO Over a year ago

Not entirely true, if i == len-1 and fi < se then i will be equal to len. You need the input data to be able to correctly analyze/debug this.

MarkO Over a year ago

Nope, the i++ happens at the location of your //and later comment, and I see no continue or break statement.

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