Error: "Could not open input file" when running .bat file

Question

I have a script in a file .bat that I need to run in Ubuntu's terminal. I run it ($./execute.bat) and I get the following error in a line:

"Could not open input file: prepare.php"

In the line inside the file, there is the command:

php prepare.php

The file prepare.php is in the same directory of execute.bat and has all permissions (chmod 777)

Why I get this error and how can I solve it?

.bat is a windows-ism. is that execute.bat a properly constructed shell script, with a shebang and all? — Marc B
– Marc B, Commented Jul 14, 2014 at 16:38
Thanks. I added, at the first line: #!/bin/sh. Then, I converted the file into a .sh and worked. — Danilo
– Danilo, Commented Jul 14, 2014 at 20:59

Cjmarkham · Accepted Answer · 2014-07-14 13:57:48Z

1

You are getting the error because the bat file cannot open prepare.php due to permissions.

Set the right permissions on prepare.php and it should be fine.

answered Jul 14, 2014 at 13:57

Cjmarkham

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1 Comment

I set all permissions for prepare.php (chmod 777) and still get the same error.