Save output of each command inside for loop

Question

I need to save the output for each command inside the for loop. My code is given below but it is not saving the log files.

count=60
for d in /afs/cern.ch/user/r/rasharma/work/TBA/Data/Run06*
do
        echo $d
        echo "./shrd51_EventBuilderVFAT.sh $d"
        ./shrd51_EventBuilderVFAT.sh $d | tee $count_EventBuilder.log
        echo "./shrd51_TrackFinder.sh $d"
        ./shrd51_TrackFinder.sh $d | tee $count_TrackFinder.log
        echo "./shrd51_Analyzer.sh $d 0$count"
        ./shrd51_Analyzer.sh $d 0$count | tee $count_Analyzer.log
        count=$((count+1))
done

And if you are appending, you may want to clear out (empty) your files at the start of the script somewhere with > file — Mark Setchell
– Mark Setchell, Commented Aug 13, 2014 at 7:08
@thatotherguy not working. And I don't need to append. Whenever I will run this I need to recreate a new file. — ramkrishna
– ramkrishna, Commented Aug 13, 2014 at 7:34
@MarkSetchell I don't need to append. Also I tried ">" instead of "| tee" but it didn't worked. — ramkrishna
– ramkrishna, Commented Aug 13, 2014 at 7:35

l0b0 · Accepted Answer · 2014-08-13 12:53:29Z

6

The issue is that $count_Analyzer.log is expanded like ${count_Analyzer}.log, that is, the value of the variable count_Analyzer followed by the string .log. Since that variable doesn't exist, you'll have a hidden file .log with all the output.

You want ${count}_Analyzer.log.

Good luck finding particles!

edited Aug 13, 2014 at 12:53

answered Aug 13, 2014 at 7:21

l0b0

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