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Just a short question regarding multidimensional arrays in C#.

How can I check if one row of a multidimensional array contains a non-Zero value? In Matlab, the "any"-command does exactly what I need.

Finally I need to put the request into a while condition. Means in Matlab: while(any(array[1,2,:])) --> which means: while(any-entry-of-the-row-is-not-Zero)...

I tried already the Array.Exists() or Array.Find() but it seems to work only with one-dimensional arrays.

Thanks

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  • show some code please ? i want to know the type of array ? Commented Aug 29, 2014 at 6:05
  • 1
    just a foreach and if statement would be enough. Commented Aug 29, 2014 at 6:05

1 Answer 1

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You have a couple options

myMultiArray.Any(row => row.Contains(Something));

or as Sriram Sakthivel Suggested

foreach(var row in myMultiArray)
    if(row.Contains(Something)
        //Found it!

foreach(var row in myMultiArray)
    if(row.IndexOf(Something) >= 0)
        //Found it!

More spefically to your question

myMultiArray.Any(row => row.Any(cell => cell != 0));

foreach(var row in myMultiArray)
    foreach(var cell in myMultiArray)
        if(cell != 0)
            //Found it!

for(int i = 0; i < array.GetLength(0); i++)
    for(int j = 0; j < array.GetLength(1); j++)
         if(array[i,j] != 0)
             //Do Something

MSDN Information

Any

Contains

IndexOf

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5 Comments

Thanks for the answer... Actually the Any command would be great, but I can't use it cause i generated a int[,,] array. I can use the foreach-possibility. I would have to work with List<List<int>> if I would like to use the C# Any-Command, right?
No worries, hope it helps
@Krus - The Any Command works on an IEnumerable which an array is, so no, you shouldn't need to use a list
With a one-dimensional array it works, but as soon as I change the array to an int[,] array, I can't use the Any-Command anymore...
@Krus - I got confused with 2d arrays and multidimentional ones earlier (had a coffee now!) I've attached some code that should do what you are looking for (without linq)

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