Unable to run the unix shell script

Question

    #!/bin/ksh
    echo -n "enter the 1 to convert lower to upper or 2 convert upper to lower"
    read n
    echo -in_str "Enter the string here"
    read in_str
    echo $n
    echo $in_str
    if [ $n -eq 1 ] then
        $ echo $in_str| awk '{print toupper($0)}'
    elif [ -n -eq 2 ] then
        $ echo $in_str| awk '{print tolower($0)}'
    else
        echo "please select the correct choice"
    fi

Getting error: else unexpected i am unable to run the above code

Alternatives for awk are typeset -u in_str and tr '[:upper:]' '[:lower:]' — Walter A
– Walter A, Commented Sep 8, 2014 at 7:24

John Zwinck · Accepted Answer · 2014-09-01 06:51:27Z

1

This:

if [ $n -eq 1 ] then

Needs to be this:

if [ $n -eq 1 ]; then

Or this:

if [ $n -eq 1 ]
then

answered Sep 1, 2014 at 6:51

John Zwinck

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2 Comments

Ranjith Kumar Over a year ago

Thanks a lot guys am very new to unix shell scripting

NeronLeVelu Over a year ago

assuming $n is not blank (or null but normaly not after the read). If not it could be ${n:-9} to assign (if blank/null) to 9 so -eq could be used

Elliott Frisch · Accepted Answer · 2014-09-01 06:52:31Z

1

You need semicolon(s) before then.And you have extra $ symbols. I think you wanted something like this

if [ $n -eq 1 ]; then
    echo $in_str| awk '{print toupper($0)}'
elif [ $n -eq 2 ]; then
    echo $in_str| awk '{print tolower($0)}'
else
    echo "please select the correct choice"
fi

At least it seems to work here.

answered Sep 1, 2014 at 6:52

Elliott Frisch

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1 Comment

paxdiablo Over a year ago

Actually, I'm pretty certain you need then on the elif as well.

paxdiablo · Accepted Answer · 2014-09-01 06:51:29Z

0

$ echo $in_str| awk '{print toupper($0)}'

???

I don't think you want that $ character at the front of that line (or the other echo line either).

In addition, if you want then on the same line as your if, it should be:

if [ $n -eq 1 ] ; then

answered Sep 1, 2014 at 6:51

paxdiablo

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