Typescript wrapper for console.log with variable number of arguments

Question

I want to create a wrapper in TypeScript around console.log like this:

var mylog = (...args: any[]) => { console.log(args); };

So I loglike this:

if (!!mylog) mylog('text', variableA, variableB);

And can set it to null to disable logging.

Problem is: this doesn't work!

Wouldn't it be simpler to not do if(!!myLog) and instead set it to an empty function if you want to disable logging? — Benjamin Gruenbaum
– Benjamin Gruenbaum, Commented Sep 14, 2014 at 10:29

basarat · Accepted Answer · 2014-09-14 10:34:25Z

9

It works fine:

var mylog = (...args: any[]) => { console.log(args); };

if (!!mylog) mylog('text', 1, 2); // ['text',1,2]

mylog = null; 

if (!!mylog) mylog('text', 1, 2); // nothing printed

Perhaps you don't want it to print as an array. You can just use apply:

var mylog = (...args: any[]) => { console.log.apply(console,arguments); };

answered Sep 14, 2014 at 10:34

basarat

278k60 gold badges475 silver badges528 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

jiroch Over a year ago

You can also simplify apply with spread syntax: var mylog = (...args: any[]) => { console.log(...args) }

Collectives™ on Stack Overflow

Typescript wrapper for console.log with variable number of arguments

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related