Using "-Filter" with a variable

Question

I try to filter out something like this:

Get-ADComputer -Filter {name -like "chalmw-dm*" -and Enabled -eq "true"} ...

This works like a charm and gets exactly what I want...

Now I want the "name -like ..." part as a variable like this:

Get-ADComputer -Filter {name -like '$nameregex' -and Enabled -eq "true"} |

I checked several questions (for example, PowerShell AD Module - Variables in Filter), but this isn't working for me.

I tried it with the following:

$nameRegex = "chalmw-dm*"
$nameRegex = "`"chalmw-dm*`""

And also in the Get-ADComputer command with those ' and without.

Could anyone give me some hints?

variables are not interpolated in single quote strings.

n0rd
– n0rd

2015-08-20 14:59:38 +00:00
Commented Aug 20, 2015 at 14:59 — n0rd
– n0rd, Commented Aug 20, 2015 at 14:59

mklement0 · Accepted Answer · 2018-03-29 23:04:45Z

17

You don't need quotes around the variable, so simply change this:

Get-ADComputer -Filter {name -like '$nameregex' -and Enabled -eq "true"}

into this:

Get-ADComputer -Filter {name -like $nameregex -and Enabled -eq "true"}

Note, however, that the scriptblock notation for filter statements is misleading, because the statement is actually a string, so it's better to write it as such:

Get-ADComputer -Filter "name -like '$nameregex' -and Enabled -eq 'true'"

Related. Also related.

And FTR: you're using wildcard matching here (operator -like), not regular expressions (operator -match).

edited Mar 29, 2018 at 23:04

mklement0

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answered Sep 19, 2014 at 9:44

Ansgar Wiechers

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Comments

walid toumi · Accepted Answer · 2014-09-19 09:47:00Z

1

Add double quote

$nameRegex = "chalmw-dm*"

-like "$nameregex" or -like "'$nameregex'"

answered Sep 19, 2014 at 9:47

walid toumi

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Comments

TylerH · Accepted Answer · 2020-02-29 02:15:44Z

0

Try this:

$NameRegex = "chalmw-dm"  
$NameR = "$($NameRegex)*"
Get-ADComputer -Filter {name -like $NameR -and Enabled -eq $True}

edited Feb 29, 2020 at 2:15

TylerH

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answered Feb 29, 2020 at 1:30

David Sanchez

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Comments

Peter Mortensen · Accepted Answer · 2017-06-04 10:40:07Z

-1

Or

-like '*'+$nameregex+'*'

if you would like to use wildcards.

edited Jun 4, 2017 at 10:40

Peter Mortensen

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answered Aug 20, 2015 at 14:55

user5248098

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