How to replace a sub-string in java of form " :[number]: "
example:
string="Hello:6:World"
After replacement,
HelloWorld
4 Answers
ss="hello:909:world";
do as below:
String value = ss.replaceAll("[:]*[0-9]*[:]*","");
5 Comments
Avinash Raj
just
:\\d*: would be enough.
WannaBeCoder
* is for 0 or more characters if you want to ensure at least one character then use + instead of *
wumpz
This regexp is not correct. It replaces single standing : and numbers without surrounded by :. It would Make "Hello 5 World" as well to "Hello World". So this is what the QE wants???
WannaBeCoder
+ would mean that there has to be at least one : followed by at least one digit followed by at least one :
WannaBeCoder
String value = ss.replaceAll(":[0-9]+:",""); would do what other commentators are saying.
You can use a regex to define your desired pattern
String pattern = "(:\d+:)";
string EXAMPLE_TEST = ':12:'
System.out.println(EXAMPLE_TEST.replaceAll(pattern, "text to replace with"));
should work depending on what exactly you want to replace...
1 Comment
Avinash Raj
did you check your pattern?
Do like this
String s = ":6:";
s = s.replaceAll(":", "");
answered Nov 3, 2014 at 9:22
Prabhakaran Ramaswamy
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Comments
Edit 1: After the question was changed, one should use
:\d+:
and within Java
:\\d+:
This is the answer for replacing :: as well.
This is the regexp you should use:
:\d*:
And here is a running JavaCode snipped:
String str = "Hello :4: World";
String s = str.replaceAll(":\\d*:","");
System.out.println(s);
One problem with replaceAll is often, that the corrected String is returned. The string object from which replaceAll was called is not modified.
2 Comments
k-nut
since
* matches zero repetitions as well though this will also match :: you should probably use :\d+: (one or more repetitions) depending on which is the desired behavior.wumpz
Strange. The question was edited. Before there was the sentence: "I want to replace :: as well. Hence I used *.
:\\d+:?