Check whitespace in a Python string

You are using isspace which says

str.isspace()

Return true if there are only whitespace characters in the string and there is at least one character, false otherwise.

For 8-bit strings, this method is locale-dependent.

Here is a neat method that illustrates the flexibility of list comprehensions. It is a helper method that checks to see if a given string contains any whitespace.

Code:

import string
def contains_whitespace(s):
    return True in [c in s for c in string.whitespace]

Example:

>>> contains_whitespace("BB")
False
>>> contains_whitespace("B B")
True

This can, of course, be extended to check if any string contains an element in any set (rather than just whitespace). The previous solution is a neat, short solution, but some may argue it is hard to read and less Pythonic than something like:

def contains_whitespace(s):
    for c in s:
        if c in string.whitespace:
            return True
    return False

Since you are looking for more than just a simple ' ' where you could use ' ' in tgt you can use any:

for s in ('B ', 'B B', 'B\nB', 'BB'):
    print repr(s), any(c.isspace() for c in s)

Prints:

'B ' True
'B B' True
'B\nB' True
'BB' False

user = 'B B'
for x in user:
    if x.isspace():
        print("no")
    else:print("yes")

you need to loop over it to check for all element, but the above code will not work as you expect.

use a helper function:

def space(text):
    if ' ' in text:
        return True
    else: return False

demo:

>>> ' ' in 'B B'
True
>>> ' ' in 'BB'
False

use in to check

if you want to use isspace:

def space(text):
    for x in text:
        if x.isspace():
            return True
    return False

Instead of returning True or False you can return Desired string too:

>>> def space(text):
...     if ' ' in text:
...         return " yes Spaces"
...     else: return " No Spaces"
... 
>>> space('B B')
' yes Spaces'
>>> space('BB')
' No Spaces'

There are already good answers to your question. Here is a way to get total number of spaces (or any other char) in string

>>> "I contain 3 spaces".count(" ")
3
>>> "Nospaces".count(" ")
0

You can use str.split to check if a string contains spaces:

>>> ''.split()
[]
>>> '  '.split()
[]
>>> 'BB'.split()
['BB']
>>> ' B '.split()
['B']
>>> 'B B'.split()
['B', 'B']

So you can check as

def hasspace(x):
    if x:
        s = x.split()
        return len(s) == 1 and x == s[0]
    return False

If you are only trying to check for whole words in the string (i.e., you are not worried about surrounding spaces that could be removed by x.strip()), the condition x == s[0] is no longer necessary. The check becomes a single statement:

def hasspace(x):
    return x and len(x.split()) == 1

Now you can do

if hasspace(user):
    print("NO!!!")
else:
    print("YES!!!")

You can loop through the string and check for whitespaces.

make a variable 'is_there_whitespace'

as its value, give it the length of whitespce found

If its greater than 0 boom you got white space.

user = "B B"

is_there_whitespace = len([True for x in user if x.isspace()])

print(f"Is there white space? {is_there_whitespace>0}.")
print(f"Amount of white spaces found:{is_there_whitespace}")

> Is there white space? True.
> Amount of white space found:1.

In [1]: a<br>
Out[1]: ' b\t\n'

In [2]: (' ' in a)or('\t' in a)or('\n' in a)<br>
Out[2]: True

To efficiently check if there is any whitespace character in a given string:

any(map(str.isspace, mystr))

Also, as previously answered by dawg, another way to write it is:

any(char.isspace() for char in mystr)