Lua: RegEx to Pattern

Question

Simple problem...I need to turn this RegEx pattern...

"\[\"([0-9]+)\"\]"

into a Lua pattern.

I am doing this to replace a bunch ["X"] lines with just [X] in a string where X is any number from -∞ or +∞...so that's about the only limitation. I need to port this to Lua patterns so I can use it in String.gsub.

Find: "\[\"([0-9]+)\"\]"

Also, how do I just remove the " " around the number? I need a pattern for that. If someone could help me out, I would appreciate it.

Avinash Raj · Accepted Answer · 2014-12-02 00:14:58Z

2

You could try like this.

> f = "foo [\"12\"] bar"
> x = string.gsub(f, "%[\"(%d+)\"%]", "[%1]")
> print(f)
foo ["12"] bar
> print(x)
foo [12] bar

\d which matches any digits would be represented as %d in lua.

edited Dec 2, 2014 at 0:14

answered Dec 2, 2014 at 0:08

Avinash Raj

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2 Comments

Etan Reisner Over a year ago

I'd probably have suggested '%["(%d+)"%]' instead to avoid the confusion of needing to escape the embedded double quotes.

G.T.D. Over a year ago

Thanks, that worked perfectly. As to Etan's suggestion, I see the reasoning, but I like " better and the escaping is not a huge problem for me. :) Thanks guys.

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