Java fill 2d array with 1d arrays

Question

Whats the nicest way to fill up following array:
From main:

String[][] data = new String[x][3]; 

for(int a = 0; a < x; a++){ 
    data[a] = someFunction();
}

Function I am using..:

 public String[] someFunction(){
     String[] out = new String[3];

     return out;
 }

Is it possible to do something like this? Or do I have to fill it with for-loop?

With this code im getting error "non-static method someFunction() cannot be refferenced from static content ---"(netbeans) on line data[a] = someFunction();

You could try this out, perhaps? Not sure how you want to produce the data for the array elements... — laune
– laune, Commented Jan 8, 2015 at 12:01

Eran · Accepted Answer · 2015-01-08 12:12:26Z

1

You have to specify how many rows your array contains.

String[][] data = new String[n][];

for(int i = 0; i < data.length; i++){
    data[i] = someFunction();
}

Note that someFunction can return arrays of varying lengths.

Of course, your someFunction returns an array of null references, so you still have to initialize the Strings of that array in some loop.

I just noticed the error you got. Change your someFunction to be static.

edited Jan 8, 2015 at 12:12

answered Jan 8, 2015 at 12:02

Eran

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5 Comments

Vedran Over a year ago

I did specify. String[][] data = new String[x][3]; x*3 and someFunction gives String[] out = new String[3];

Eran Over a year ago

@Vedran My mistake. I thought you meant that x implies an arbitrary length.

Vedran Over a year ago

Any idea what I could do?

Eran Over a year ago

@Vedran change your someFunction method to static.

Vedran Over a year ago

oh. totally missed that. Thanks for your help!

Tim Hallyburton · Accepted Answer · 2015-01-08 14:58:54Z

0

Change your someFunction() by adding "static".

You also should consider using an ArrayList for such tasks, those are dynamic and desinged for your purpose (I guess).

public static void main(String[] args){

    int x = 3;

    String[][] data = new String[x][3]; 

    for(int a = 0; a < x; a++){ 
        data[a] = someFunction();
    }

}

public static String[] someFunction(){
     String[] out = new String[3];
     return out;
 }

Greetings Tim

answered Jan 8, 2015 at 14:58

Tim Hallyburton

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