How to find ids of record from array of records using Ruby 2.0

Question

consider here is array of records below

   [#<IpAddress id: 26, ip: "12.10.20.11", latitude: '0.3155460609',  longitude: '0.74357158' ,
    #<IpAddress id: 27, ip: "12.10.20.12", latitude: '0.3155460609',  longitude: '0.74357158',
    #<IpAddress id: 29, ip: "12.10.20.30", latitude: '0.3155460609', longitude: '0.74357158',
    #<IpAddress id: 44, ip: "127.0.0.1", latitude: '0.3155460609', longitude: '0.7435715',
    #<IpAddress id: 52, ip: "127.0.0.3", latitude: '0.3155460609', longitude: '0.743571' ,
    #<IpAddress id: 55, ip: "14.30.20.13", latitude: '0.3155460609', longitude: '0.74357']

I want to get ids of same ip's in this array by not considering last dot value of ip address in form of hash like below.

{12.10.20 => [26,27,29] , 127.0.0 => [44,52], 14.30.20 => [55]}

Any trick?

Thanks

Amit Kumar Gupta · Accepted Answer · 2015-01-23 06:53:33Z

1

h = Hash.new {[]}
records.each { |ipaddr| ip = ipaddr.ip; h[ip[0...ip.rindex(".")]] <<= ipaddr.id }
puts h
# => {"12.10.20"=>[26, 27, 29], "127.0.0"=>[44, 52], "14.30.20"=>[55]}

answered Jan 23, 2015 at 6:53

Amit Kumar Gupta

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halex · Accepted Answer · 2015-01-23 07:00:46Z

1

array_of_ips.group_by{|a| a.ip[0, a.ip.rindex(".")]}.each{|_, v| v.map!{|a| a.id}}

answered Jan 23, 2015 at 7:00

halex

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Naveed · Accepted Answer · 2015-01-23 10:20:46Z

1

Fetch records from database with first three IP groups( demo ), then simple group will do the trick

IpAddress.select("ip_addresses.id, substring(ip from '(([0-9]*\.[0-9]*){2})') as short_ip)").group_by(&:short_ip)

This will return hash of related IPAddress. If you are looking for ids instead of Objects add another loop :)

    IpAddress.select("ip_addresses.id, substring(ip from '(([0-9]*\.[0-9]*){2})') as short_ip)").group_by(&:short_ip).inject({}).map do |key, records| { key: records.pluck(:id)} end

edited Jan 23, 2015 at 10:20

answered Jan 23, 2015 at 8:21

Naveed

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