Creating an array filled with array-variables in cshell

Question

I want to populate in array in chsell such that each index in the array will be an array itself. That is, if I ran

set a = ( `seq 1 2 10` )
set b = ( `seq 2 2 10` )
set array = ( $a $b )
echo $array[2]

then the return would be 2 4 6 8 10 (which is $b) instead of 3 (which is $a[2]).

Ultimately I could get away with declaring a bunch of variables, but it will make my code a mess. This would be similar to a cell in Matlab if that helps clarify the end result. Is there anyway to do this?

fork2execve · Accepted Answer · 2016-01-11 21:37:30Z

1

Csh doesn't have arrays, it only has lists of words, and is only a very limited programming language.

Given your constraints for a maintainable "clean" way of doing this in csh, the answer is no there is no solution.

This is very easy in a language such as Perl, which is designed for situations like this where the standard shells and UNIX utilities run out of steam.

answered Jan 11, 2016 at 21:37

fork2execve

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1 Comment

climatefreak Over a year ago

Luckily, I no longer work with the people who required Csh for scripting. Thanks for enlightening me to the exact limitations in this situation, though!

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