Create multiple files with same names in linux

Question

I need to create 8 txt files wiht name text[x], where X is number from 1 to 8. Is there any simple construction to do that? I thought to use iteration. The simple method like:

touch text1.txt text2.txt text3.txt text4.txt text5.txt text6.txt text7.txt text8.txt

is not acceptable.

@gniourf_gniourf that's the answer, so shouldn't be a comment! — Tom Fenech
– Tom Fenech, Commented Feb 4, 2015 at 12:52

Barton Chittenden · Accepted Answer · 2015-02-04 19:34:46Z

3

You can do this without the loop by using brace expansion in the file name:

touch text{1..8}.txt

See brace expansion in the bash man pages. Unlike wildcard expansion, the file names do not have to exist for brace expansion.

answered Feb 4, 2015 at 19:34

Barton Chittenden

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Comments

William Cates · Accepted Answer · 2015-02-04 13:03:18Z

1

Basic for loop construction with echoing the iteration 1 - 8 as variable 'i', which you use as a piece of the file name created by touch.

for i in `echo {1..8}`
do touch text$i.txt
done

As a one liner:

for i in `echo {1..8}`; do touch text$i.txt; done

But, I think you just had the answer in a simpler format in your comments.

answered Feb 4, 2015 at 13:03

William Cates

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1 Comment

Tom Fenech Over a year ago

As you've suggested, you don't need to use a loop anyway but if you're going to, you certainly don't need to use process substitution as well. for i in {1..8} would be sufficient.

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