Count number of a group array in array in php

Question

I want to count the number of a group array in the array. Example

$arr1 = [61,41,41,61,89,90]
$arr2 = [61,41]
$result = 2    //found 61,41 in $arr1  2 time;

Or Example

$arr1 = [89,61,41,41,61,90]
$arr2 = [61,41,89]
$result = 1    //found 61,41,89 in $arr1  1 time;

How to write the code, or concept?

The second example you provided does not make any sense. Could you elaborate a bit more? — kidA
– kidA, Commented Feb 16, 2015 at 8:51
What if, 1 value appears once and the other appears 3 times would the result be 4? — Antony D'Andrea
– Antony D'Andrea, Commented Feb 16, 2015 at 8:56

noufalcep · Accepted Answer · 2015-02-16 08:54:48Z

1

I hope this will help you..

$arr1 = array(61,41,41,61,89,90);
$arr2 = array(61,41);

$count = array_count_values($arr1); //count values from arr1

$result = array();
foreach($arr2 as $row) {
    $result[$row] = array_key_exists($row, $count) ? $count[$row] : 0;
}

echo min($result);

$arr2 = [61,41] output: 2

$arr2 = [61,41,89] output: 1

answered Feb 16, 2015 at 8:54

noufalcep

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deceze · Accepted Answer · 2015-02-16 09:04:14Z

1

$arr1 = array(61,41,41,61,89,90);
$arr2 = array(61,41);

$occurrences = min(
    array_count_values(array_intersect($arr1, $arr2)) + array_fill_keys($arr2, 0)
);

Arguably a somewhat obscure solution, but a single expression. Returns the number that the entire $arr2 set occurs in $arr1.

answered Feb 16, 2015 at 9:04

deceze♦

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