Socket Reset Exception - Java

Question

I am trying to send a ByteBuffer array over a socket on the port 25565 on the address "localhost". But for some reason, Java is throwing a connection reset exception when doing input.read(). Could someone please tell me whats going on?

Sender:

private static Socket socket;

public static void main(String[] args) throws IOException {
    socket = new Socket("localhost", 25565);
    String Password = "1234";
    ByteBuffer Buffer = ByteBuffer.allocate(1 + Password.getBytes().length);
    Buffer.put((byte) 0x00);
    Buffer.putShort((short) Password.getBytes().length);
    Buffer.put(Password.getBytes());
    DataOutputStream output = new DataOutputStream(socket.getOutputStream());
    output.write(Buffer.array());
}

public static void sendBytes(byte[] myByteArray) throws IOException {
    DataOutputStream output = new DataOutputStream(socket.getOutputStream());
    output.write("LOL".getBytes());
    output.flush();
}

Receiver:

public static void main(String[] args) {
    try {
        ServerSocket ServerSocket = new ServerSocket(25565);
        System.out.println("Waiting for connection...");
        Socket socket = ServerSocket.accept();
        DataInputStream Input = new DataInputStream(new BufferedInputStream(socket.getInputStream()));
        System.out.println(Input.read());
        ServerSocket.close();
        socket.close();
    } catch (Exception e) {
        if(e instanceof SocketTimeoutException) {
            System.out.println("THE SOCKET TIMED OUT!");
        }
        else {
            e.printStackTrace();
        }
    }
}

Stack trace:

java.net.SocketException: Connection reset
at java.net.SocketInputStream.read(SocketInputStream.java:189)
at java.net.SocketInputStream.read(SocketInputStream.java:121)
at java.io.BufferedInputStream.fill(BufferedInputStream.java:246)
at java.io.BufferedInputStream.read(BufferedInputStream.java:265)
at java.io.FilterInputStream.read(FilterInputStream.java:83)
at net.networking.Receiver.main(Receiver.java:17)

NOTE: Yes, I do know that just using input.read() will not get the whole ByteBuffer array I'm trying to send. But right now I just want to read the first byte and print it out to the console.

Remy Lebeau · Accepted Answer · 2015-02-18 03:20:49Z

You're not closing the connection in the sender, so it gets reset when the process exits.

private static Socket socket;

public static void main(String[] args) throws IOException {
    socket = new Socket("localhost", 25565);
    String Password = "1234";
    sendBytes(Password.getBytes());
    output.close();
}

public static void sendBytes(byte[] myByteArray) throws IOException {
    ByteBuffer Buffer = ByteBuffer.allocate(3 + myByteArray.length);
    Buffer.put((byte) 0x00);
    Buffer.putShort((short) myByteArray.length);
    Buffer.put(myByteArray);
    DataOutputStream output = new DataOutputStream(socket.getOutputStream());
    output.write(Buffer.array());
    output.flush();
}

You're only reading one byte and then closing the connection. You need to read the entire transmission. If you close a socket with unread data still pending, the connection is reset. Also, if you want to handle exceptions separately, catch them separately. Don't use instanceof.

public static void main(String[] args) {
    try {
        ServerSocket ServerSocket = new ServerSocket(25565);
        System.out.println("Waiting for connection...");
        Socket socket = ServerSocket.accept();
        DataInputStream Input = new DataInputStream(new BufferedInputStream(socket.getInputStream()));
        byte b = Input.readByte();
        short dataLen = Input.readShort();
        byte[] data = new byte[dataLen];
        Input.readFully(data);
        // use data as needed...
        System.out.println("Data received");
        Input.close();
        ServerSocket.close();
    } catch (SocketTimeoutException e) {
        System.out.println("THE SOCKET TIMED OUT!");
    } catch (Exception e) {
        e.printStackTrace();
    }
}

Still doesnt work, tried what you said. Could you send me the exact code fix you were proposing? I just want to make sure I put what you mean.

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