How to implement factory pattern when using mongoose?

Question

I'm using mongoose to work with my MongoDB documents and have thee models:

module.exports = mongoose.model('Doc', mongoose.Schema({
    type: 'doc'
}, collection: "doc");

module.exports = mongoose.model('Folder', mongoose.Schema({
    type: 'folder'
}, collection: "doc");

module.exports = mongoose.model('Unit', mongoose.Schema({
    type: 'unit'
}, collection: "doc");

At some point (on ajax request coming for example) I need to create model at several type:

app.post('/doc/create/:type', function (req, res, next) {
    var type = req.params.type;
    var data = req.body;

    // how to create model based on incoming type here?
    // var model = new Factory.create(type); ???
});

I need to know best practices to work with similar models and create instance from factory or something else.

Please share your experience.

ItalyPaleAle · Accepted Answer · 2015-02-23 14:53:30Z

1

You can get a model from a string by using something like:

var mongoose = require('mongoose')
var model = mongoose.model('Unit')

PS: If this is the solution to your problems, I'm wondering if the way you are designing your database models is actually the proper one! Can't you create a single model "Doc" with an indexed "type" property? It would be more efficient in many ways.

answered Feb 23, 2015 at 14:53

ItalyPaleAle

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3 Comments

Erik Over a year ago

Thanks for the answer. I can't create single model because each other has different fields.

ItalyPaleAle Over a year ago

You could just define all the possible fields and then not use them (fields that are 'undefined' are not stored in Mongo by Mongoose)

Erik Over a year ago

I don't want to store all possible fields in single model due to separate logic and data. I'm looking for solution to create factory.

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