How to fire code only when script.js is ran via node.js?

Question

I have a script.js that I either use on client side html page. Either via nodejs.

How can I get a function to fire only if the script is run via nodejs ?

Check for something that should only exist in the browser (document) or node (exports). This is how underscore does it github.com/jashkenas/underscore/blob/master/… — Jake Burkhead
– Jake Burkhead, Commented Mar 1, 2015 at 1:11

Hugolpz · Accepted Answer · 2015-03-14 23:16:12Z

1

if (typeof define === "function" && define.amd) define(function() { return queue; });
else if (typeof module === "object" && module.exports) module.exports = queue;
else this.queue = queue;

Underscore does something such :

  if (typeof exports !== 'undefined') {
    if (typeof module !== 'undefined' && module.exports) {
      exports = module.exports = _;
    }
    exports._ = _;
  } else {
    root._ = _;
  }

But this seems to assess node.modules. Secondly, if someone could confirm what each case is, that would help !

edited Mar 14, 2015 at 23:16

answered Mar 1, 2015 at 1:24

Hugolpz

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Matt Harrison · Accepted Answer · 2015-03-14 23:20:17Z

1

fabric.js has a useful one-liner:

var isLikelyNode = typeof Buffer !== 'undefined' && typeof window === 'undefined';

answered Mar 14, 2015 at 23:20

Matt Harrison

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1 Comment

Hugolpz Over a year ago

None of the answers solved my case. Indeed, i am creating a virtual windows via jsdom, so my js script always is in a browser, real or virtual. I haven t tested these answers for strickly serverside use cases. So i can neither valid your, nor my answer. But I can +1 some of your answer so you get to 2000 points :)

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