To get a sub array of an array, we can do something like:
@x = (1,2,3,4,5,6);
@y = @x[1 .. 4]
What I have reference to an array
$x = [1,2,3,4,5,6];
What is an easy way to get a reference to a sub array
$y = $x->[1 .. 4]; #doesn't work.
Thanks.
The equivalent of
my @x = (1,2,3,4,5,6);
my @y = @x[1..4]
is
my $x = [ (1,2,3,4,5,6) ]; (Parens can be removed)
my $y = [ @$x[1..4] ];
which is basically the same as
my @x = (1,2,3,4,5,6); my $x = \@x;
my @y = @$x[1..4]; my $y = \@y;
There's no such thing as a sub array or a reference to one.
I dont think that is possible the better way is to take subarray in new array and then take the reference to that new array.
@x = (1,2,3,4,5,6);
@y = @x[1 .. 4];
my $arrf = \@y
print "@$arrf";
An array slice isn't a variable, you can't take a reference to it. But if you want a reference to a new anonymous array created from a slice of the original array you can do
$y = [ @$x[1 .. 4] ];
where @$x[1 .. 4] slices @$x in the same way as @x[1 .. 4] slices @x, and the
[ ... ] operator creates a reference to a new array. The elements of @$y are shallow copies of the elements in @$x; modifying @$y doesn't modify @$x (but if some of those elements are references, they will still reference the same data).
$y=sub{\@_}->(@$x[1..4])