how to check all object in NSMutableArray same value

Question

I have on NSMutableArray like this:

NSMutableArray *array = [NSMutableArray arrayWithObjects:@"0",@"0",@"0",@"0",@"0", nil];

now I want check if all object in my array are to same and equal to 0 doing certain work!!!. but I don't know about this. please guide me.

MmD · Accepted Answer · 2015-03-15 09:56:48Z

5

My friend try this:

NSMutableArray *array = [NSMutableArray arrayWithObjects:@"0",@"0",@"0",@"0",@"0", nil];
NSCountedSet *filter = [NSCountedSet setWithArray:array];

//this condition check number of 0 value with your array count
//if number of 0 equal to array count this means that all object in array is 0
if ([filter countForObject:@"0"] == [array count]) {
   NSLog(@"all objects are 0");
}

answered Mar 15, 2015 at 9:56

MmD

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Comments

uraimo · Accepted Answer · 2015-03-15 09:35:55Z

1

You can use the usual for statement:

for (int i = 0; i < [array count]; i++)
{
    NSString *string = [array objectAtIndex:i];
    // Check for >0
}

Or fast enumeration:

for (NSString *string in array)
{
    // Check for >0
}

I didn't fill on purpose the check part, considering that you are a iOS (i guess) beginner can i recommend a good book on iOS programming? iOS Programming: The Big Nerd Ranch Guide

edited Mar 15, 2015 at 9:35

answered Mar 15, 2015 at 9:28

uraimo

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1 Comment

MKFB Over a year ago

my friend I want check if all object in my array are to same and equal to 0 doing certain work!!!

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