Array Length is 1 in Bash scripting

Question

In the below code, the array length is 1.

Could anyone explain why, as grep output will displayed in each new line but when it is stored in the array, the array length will be 1.

How to display each line reading the array?

#!/bin/bash

NUM=()
SHORT_TEXT=()
LONG_TEXT=()

#cat /tmp/dummy2 | 
while read NUM 
do
    LONG_TEXT+=$(grep $NUM -A4 RtpLogShm.Msg | grep -vi abate | grep ^LG)
    done < /tmp/dummy2

    #cat /tmp/dummy1 | 
    while read LINE
    do
        NUM+=$(echo $LINE | awk -F':' '{print $1}')
        SHORT_TEXT+=$(echo $LINE | awk -F':' '{print $2}')
        done < /tmp/dummy1

        printf "[%s]\n" "${LONG_TEXT[@]}"
    done
done

You are not creating the LONG_TEST as an array - See this for how to store the results as an array - stackoverflow.com/questions/24890764/… — rahul
– rahul, Commented Apr 14, 2015 at 7:49

4ae1e1 · Accepted Answer · 2015-04-14 08:00:05Z

2

In bash, the syntax of appending to an array is (say we want to append an element stored in ${new_element} to an existing array ${array[@]}):

array=("${array[@]}" "${new_element}")

answered Apr 14, 2015 at 8:00

4ae1e1

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