parsing JSON with Json.Net to get the Key

Question

Searched my question and didnt find the answer, I have a JSON file like below:

{  
   "handle":"ABCD",
   "Tracks":{  
      "Design":{  
         "rating":402
      },
      "Development":{  
         "rating":1584,
         "reliability":"n/a"
      },
      "Specification":{  
         "rating":923,
         "reliability":"0.13"
      },
      "Conceptualization":{  
         "rating":895
      }
   }
}

I am getting a dynamic object of json:

dynamic dynObj;
dynObj = JsonConvert.DeserializeObject(content);

how can I get the name of "Tracks" item? I dont know how many tag like "Design" is there nor I know the name of them...

Where is your Server-Side Model? Where is that model that represents that JSON Object? — Greg
– Greg, Commented May 4, 2015 at 20:59
Well, that would be how you access it. From that model, example.Tracks for example. — Greg
– Greg, Commented May 4, 2015 at 21:01
I can get all of the track items like dynObj["Tracks"], but I want to know how many items are there and the name of them to do sth else. — MT467
– MT467, Commented May 4, 2015 at 21:03
@MT467 Is there a reason that you need to use a dynamic type? Does the JSON data returned change frequently? — tier1
– tier1, Commented May 4, 2015 at 21:13

Bas · Accepted Answer · 2015-05-04 21:21:40Z

1

In your (dynamic) scenario, don't use dynamic, it does not make sense, since you are looking for schema information about the document, which becomes unavailable through the dynamic model.

So, get a JObject by calling JObject.Parse on your JSON data.

Then, get the keys as such (taken from the JObject.Properties documentation):

foreach (var prop in myJObject.Properties()) 
{ 
    //returns 'handle' and 'Tracks' for your root object
    Console.WriteLine("{0} - {1}", prop.Name, prop.Value); 
}

Or using the enumerator of the JObject:

foreach (var kvp in myJOBject) 
{
    Console.WriteLine("{0} - {1}", kvp.Key, kvp.Value);
}

answered May 4, 2015 at 21:21

Bas

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4 Comments

moarboilerplate Over a year ago

^this, or any of the JsonConvert.DeserializeObject overloads that take a type parameter.

MT467 Over a year ago

I know handle and tracks are there, how about items under tracks?

Bas Over a year ago

@MT467 Repeat the same logic for the Value of the property.

Bas Over a year ago

@moarboilerplate We don't want a strongly typed value, as the type of the returned object is unknown, as I understand.

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