Implement function without name in Typescript

Question

I'm trying to implement a function without name like this:

interface I {
    (name: string): void;    
}

class C implements I {
    (name: string):void { }
}

I want to use C like this, but it doesn't work:

C("test");

I can write it in javascript and use the interface declaration: I("test");

But I want to do the same in Typescript.

David Sherret · Accepted Answer · 2015-06-06 03:14:30Z

13

You can't do that on classes, but you can do it with a regular function:

interface I {
    (name: string): void;
}

var C: I = function(name: string) {

};

C("test"); // ok
C(1);      // compile error

Then if you change your interface you will be notified by a compile error to change the C function.

edited Jun 6, 2015 at 3:14

answered Jun 5, 2015 at 21:26

David Sherret

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1 Comment

Dyanek Over a year ago

What happens if you have many methods in the interface? For example: interface I { (name: string): void; (number: number): void; awesomeMethod(): string; }

Ryan Cavanaugh · Accepted Answer · 2015-06-05 20:44:20Z

2

Classes can't have call signatures in TypeScript.

answered Jun 5, 2015 at 20:44

Ryan Cavanaugh

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