Simple JavaScript Swap function

Question

I'm having difficulty in correcting the syntax error for image swap. I would appreciate if you can help me out as below?

function swap(i, s)
{
   var d = document.images;
   d ? d[i].src=s : null;
}

deadboy · Accepted Answer · 2015-06-09 14:51:23Z

1

I think you want something like this

function swap(i, s) {
    var d = document.images;
    if (i >= 0 && i < d.length) {
        d[i].src = s;
    }
}

answered Jun 9, 2015 at 14:43

deadboy

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2 Comments

Much appreciated, Evin.

I made a slight mistake so I edited the question and fixed it, @Irishgirl