Java: get all method parameters as Object array

Question

Is it possible to do this:

void foo(Bar b, FooBar fb){
    Object[] args=getArgs() //Contains the parameters b & fb
}

And if yes, how?

(I dont know the name and the number of parameters)

Yes you do know the name and number of arguments: Two arguments b and fb. — Nayuki
– Nayuki, Commented Jun 9, 2015 at 19:47
Of course you know the names of the parameters. They're declared right above. — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Jun 9, 2015 at 19:47
Above ways are straightforward. If, on the other hand, you are looking for an arguments object a-la JavaScript, then no, we don't have access to such an object in Java. — Kedar Mhaswade
– Kedar Mhaswade, Commented Jun 9, 2015 at 19:48

Nayuki · Accepted Answer · 2015-06-09 19:46:23Z

5

No, Java does not support a simple, generic way to pack all the method arguments into an array. This is pretty standard for statically typed programming languages. It's generally dynamic languages like JavaScript and shell scripting languages that do allow retrieving all the arguments as an array.

answered Jun 9, 2015 at 19:46

Nayuki

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dcsohl · Accepted Answer · 2015-06-09 19:56:20Z

4

Given a method like you declare it, there is no (easy/standard) way to retrieve it as an Object[].

Now, you can always declare a method as

public void doSomething(Object... args) {
   Object o1 = args[0];  // etc
}

then you can call

doSomething(foo);
// or
doSomething(foo, bar, baz);

but you lose all type safety doing it this way; I don't really recommend it.

edited Jun 9, 2015 at 19:56

answered Jun 9, 2015 at 19:49

dcsohl

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