Creating a Menu Script

Question

I am trying to create a menu script that will execute a command when the option is selected. This is what I have so far.

#!/bin/bash

PS3='Please enter you choice: '
options=("Option 1 - File Directory?" "Option 2 - Run MyScript?" "Option 3 - ?" "4 - Quit")
Select opt in "${options[@]}"
do
       case $opt in
            "Option 1 - File Directory?")
                echo "you chose option 1"
                ;;
            "Option 2 - Run MyScript?")
                echo "you chose option 2"
                ;;
            "Option 3 - ?")
                echo "you chose option 3"
                ;;
            "Quit")
                break
                ;;
            *) echo invalid option;;
         esac
done

change Select to select and "Quit" to "4 - Quit" or otherwise — Jahid
– Jahid, Commented Jun 14, 2015 at 16:10
I need to get the script to display the current directory if option 1 is selected and also to run a shell script that I created if option 2 is selected. How do I do that and/or what are the commands? — Tyler Kelley
– Tyler Kelley, Commented Jun 14, 2015 at 16:31
echo $PWD to print current directory, path_to_the_script to run a script — Jahid
– Jahid, Commented Jun 14, 2015 at 23:45

Jahid · Accepted Answer · 2015-06-14 16:26:58Z

1

Change Select to select and "Quit" to "4 - Quit" inside case or otherwise.

Your code edited:

PS3='Please enter you choice: '
options=("File Directory?" "Run MyScript?" "?" "Quit")
select opt in "${options[@]}"
do
       case $opt in
            "File Directory?")
                echo "you chose option 1"
                ;;
            "Run MyScript?")
                echo "you chose option 2"
                ;;
            "?")
                echo "you chose option 3"
                ;;
            "Quit")
                break
                ;;
            *) echo invalid option;;
         esac
done

You can check for errors in your shell script with shellcheck.

answered Jun 14, 2015 at 16:26

Jahid

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