Regex Javascript to catch string

Question

I am using this regex ^(?:foo|bar)+|(.+)$ to catch string different from 'foo' or 'bar' but it catches string only after foo or bar and not at beginning. For example it catches ba in string foobarfooba but doesn't catch ba in string bafoobarfoo.

Demo

I suppose you didn't mean to use those ^ and $ anchors?

Bergi
– Bergi

2015-06-19 10:38:16 +00:00
Commented Jun 19, 2015 at 10:38 — Bergi
– Bergi, Commented Jun 19, 2015 at 10:38

Avinash Raj · Accepted Answer · 2015-06-19 11:20:35Z

1

Because you used the start of a line anchor. Removing the start of the line anchor also won't work for you. So I suggest you to use the below regex.

var s = "bafoobar";
var re = /foo|bar|((?:(?!foo|bar).)+)/gm;
alert(re.exec(s)[1])

DEMO

edited Jun 19, 2015 at 11:20

answered Jun 19, 2015 at 10:35

Avinash Raj

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9 Comments

Giuseppe federico Over a year ago

Ok it is perfect ,but I don't understand why with

var patt = new RegExp("foo|bar|((?:(?!foo|bar).)+)");  var res = patt.test(string);   console.log(res)//true; and string = foobarfoobarbarfoo

why res is true?

Avinash Raj Over a year ago

You need to use exec function to get the value from group index 1.

Giuseppe federico Over a year ago

This is result of exec ["foo", undefined, index: 0, input: "foobarfoobarbarfoo"].Why it match foo ?

Avinash Raj Over a year ago

It does matching foo or bar but captures only the text other than foo or bar. Check my update..

Giuseppe federico Over a year ago

Your exec solution doesn't work ad example with foobarba

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