jQuery-AJAX: Checking if Data Exists, if not "POST"

Question

I am trying to check if the data already exists in the JSON Array Object that is returned on 'GET'. IF the data already exists, I want it to ignore the data. If it does not exist I want it to "POST." Please help. It seems to be skipping the "POST" call.

  function POST(section){
     $.ajax({
        type: 'POST',
        dataType: 'json',
     async : false,
        data: JSON.stringify(section),
        url: '/api/v2/help_center/en-us/categories/200384077/sections.json',
        contentType: "application/json; charset=utf-8",

        headers: {
            "Authorization": "Basic " + btoa(username + ":" + password)
        },// end headers
        success: function (newSection) {
            console.log("Congrats! We have inserted a new section", newSection);

        },
        error: function (xhr, errorText) {
            console.log('Error ' + xhr.responseText);
        }
    })// end AJAX POST
    }

function addNewSection(name, description) {

    var section = { "section": { "position": 2, "name": name, "description": description, "content.translations.name": [{ "locale": "en-us" }] } };

    $.ajax({
        type: 'GET',
        url: '/api/v2/help_center/categories/200384077/sections.json',
        dataType: 'json',
        async : false,
        headers: {
            "Authorization": "Basic" + btoa(username + ":" + password)
        },
        success: function (mySections) {

            var naming = mySections.sections;
            $.each(naming, function (i, result) {
              if( $.inArray(name, result) == -1)
              {
                console.log("This already exists", name);
              } 

                if( !$.inArray(name, result) == -1) {
              POST(section);
              }

            });

        } // end success function
    })// end AJAX GET


}

Ben Fried · Accepted Answer · 2015-07-17 06:20:40Z

1

Remove the ! from this:

if( !$.inArray(name, result) == -1)

So you have:

if ($.inArray(name, result) == -1)

What you wrote is basically a double negative. $.inArray returns -1 when it doesn't find anything. You would never use ! with $.inArray because it can never return false.

edited Jul 17, 2015 at 6:20

answered Jul 17, 2015 at 5:59

Ben Fried

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7 Comments

Darius Castillo Over a year ago

I used if( !$.inArray(name, result) == -1) if the data doesn't exist. then "POST." Is there a better way to write it? because If i use if( $.inArray(name, result) == -1) again then i will insert duplicate data.

Ben Fried Over a year ago

if( $.inArray(name, result) == -1) already literally means "If the name is NOT in the result array". Isn't that when you want to post?

Ben Fried Over a year ago

If you want it the other way, where you post only if the name IS in the array, you'd do if( $.inArray(name, result) >= 0). Either way, you would never write !$.inArray as the function has no way of ever returning "false." It returns -1 if it doesn't find anything, or an index (0 or higher) if it does find something.

Darius Castillo Over a year ago

When using >=0 it always says the data exists in the array even when it doesn't. Any other ideas?

Ben Fried Over a year ago

You're going to have to post your code where that's happening, because there's something else going on. If $.inArray comes back with 0 or greater, it found a match...there's no way for $.inArray to get it wrong.

|

Darius Castillo · Accepted Answer · 2015-07-17 21:13:29Z

0

Looks like this worked just perfectly!!

var match = false;
$.each(naming, function(i,v){
  if(v.name == name){
         match = true;
        return false;
    }
 });
 if(!match){
  POST(section);
}

answered Jul 17, 2015 at 21:13

Darius Castillo

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