I have the following python list in
[0,1,2,'def','ghi']
Now I want to convert above into another list of tuples by discarding first list item so for e.g. I want [(1,0),(2,1),('def',2),('ghi',3)]
I have the following code
point = [0,1,2,'def','ghi']
spliltm0 = split[1:]
ls = ()
int i = 0
for a in spliltm0:
ls = (a,i++)
The above seems to be long code for Python, is there any shorter version of above code? I am super new to Python.
That code isn't Python at all, since you do int i and i++, neither of which are Python*; also, strip() and split() are methods on strings, not lists.
Your result can be achieved in a one-line list comprehension:
result = [(elem, i) for i, elem in enumerate(point[1:])]
* i++ is syntactically valid in Python, but doesn't at all do what you think it does.
You need to be clear about the basics of Python before asking in the Python Forum.
1) You cannot apply strip function on a 'list' object, It should be string object.
2) spliltm0 = split[1:], Here split is treated as string, and is not defined. Also split is a string method which should not be used as a variable for storing string.
3) int i = 0 This is a format of C/C++. Not applicable to Python
4)
for a in spliltm0:
ls = (a,i++)
i++ is not available in Python. Refer to this link (Why are there no ++ and -- operators in Python?)
strip()on a list? Also[(j,i) for i,j in enumerate(point[1:])]